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Math formulas for grade 11, grade 12 and under graduates.
In an x-y Cartesian coordinate system, equation of the circle is:
(x-a)2 + (y-b)2 = r2

sin 0° = 0
cos 0° = 1
tan 0° = 0
sin 30° = 1/2
cos 30° = (√3)/2
tan 30° = 1/(√3)
sin 45° = 1/(√2)
cos 45° = 1/(√2)
tan 45° = 1
sin 60° = (√3)/2
cos 60° = 1/2
tan 60° = √3
sin 90° = 1
cos 90° = 0
tan 90° = ∞
sinq = 1/cosecq
cosq = 1/secq
tanq = 1/cotq
sinq/cosq = tanq
sin2q + cos2q = 1
1 + tan2q = sec2q
1 + cot2q = cosec2q
sin( 90° - q ) = cosq
cos( 90° - q ) = sinq
tan( 90° - q ) = cotq
sin( 90° + q ) = cosq
cos( 90° + q ) = - sinq
tan( 90° + q ) = - cotq
sin( 180° - q ) = sinq
cos( 180° - q ) = - cosq
tan( 180° - q ) = - tanq
sin( 180° + q ) = - sinq
cos( 180° + q ) = - cosq
tan( 180° + q ) = tanq
Pythagorean Theorem:
The square of the length of the hypotenuse of a right triangle is equal to the sum of the squares of the legs
a2 = b2 + c2
a,b - two sides of the triangle connected by the right angle
c - hypotenuse of the triangle

circumference of a circle
circumference of a circle = 2 . π . r
where,
π = PI = 22/7
r = radius of circle

Area of Triangle
Area of Triangle = (1/2) . b . h
where,
h = height of triangle
b = the length of the base of triangle

Area of rectangle
Area of rectangle = l . b
where,
l = length of rectangle
b = width of rectangle

Area of circle
Area of circle = π . r 2
where,
π = PI = 22/7
r = radius of circle

Area of trapezoid
Area of trapezoid = (1/2) . (height). (base one + base two)

Area of Ellipse
Area of Ellipse = π . r1 . r2
where,
r1 = major radius
r2 = minor radius

Area of Cylinder (surface area)
Area of Cylinder (surface area) =
2 . π . r . h
where,
r = radius of cylinder
h = length of cylinder

Area of Cone (surface area)
Area of Cone (surface area) =
π . r . l
where,
r = radius of cone
l = length of side of the cone

Volume of cylinder
Volume of cylinder = π . r 2 . h
where,
π = PI = 22/7
r = radius of cylinder
h = length of cylinder

Volume of sphere
Volume of sphere = (4/3) . π . r 3
where,
π = PI = 22/7
r = radius of sphere

Volume of Cone
Volume of Cone = (1/3) . π . r 2 . h
where,
π = PI = 22/7
r = radius of Cone
h = height of cone

sin(-x) = -sin(x)
cosec(-x) = -cosec(x)
cos(-x) = cos(x)
sec(-x) = sec(x)
tan(-x) = -tan(x)
cot(-x) = -cot(x)
sin( a + b ) = sina cosb + cosa sinb
sin( a - b ) = sina cosb - cosa sinb
cos( a + b ) = cosa cosb - sina sinb
cos( a - b ) = cosa cosb + sina sinb
tan( a + b ) = (tana + tanb)
(1 - tana tanb)

tan( a - b ) = (tana - tanb)
(1 + tana tanb)

sin2a = 2 sina cosa
cos2a = cos2a - sin2a = 2cos2a - 1 = 1 - 2sin2a
tan2a = (2 tana)
(1 - tan2a)

sin3a = 3sina - 4sin3a
cos3a = 4cos3a - 3cosa
For any triangle ABC with side lengths a,b,c
Law of Cosines
c2 = a2 + b2 - 2 a b cos C
b2 = c2 + a2 - 2 c a cos B
a2 = b2 + c2 - 2 b c cos A
Law of Sines
sinA/a = sinB/b = sinC/c

cos θ cos β = cos(θ - β) + cos(θ + β)
2

sin θ sin β = cos(θ - β) - cos(θ + β)
2

sin θ cos β = sin(θ + β) + sin(θ - β)
2

sin3 θ = 3sin θ - sin 3θ
4

cos3 θ = 3cos θ + cos 3θ
4

sin3 θ . cos3 θ = 3sin 2θ - sin 6θ
32

sin4 θ = 3 - 4 cos 2θ + cos 4θ
8

cos4 θ = 3 + 4 cos 2θ + cos 4θ
8

sin4 θ . cos4 θ = 3 - 4 cos 4θ + cos 8θ
128

sin5 θ = 10 sin θ - 5 sin 3θ + sin 5θ
16

cos5 θ = 10 cos θ + 5 cos 3θ + cos 5θ
16

sin5 θ . cos5 θ = 10 sin 2θ - 5 sin 6θ + sin 10θ
512

Quadratic Equation
For the equation:
a x 2 + b x + c = 0                                
Quadratic equation solving calculator
the value of x will be
x = - b ± √ (b2 - 4 a c)
2 a

(a + b)2 = a2 + 2 a b + b2
(a - b)2 = a2 - 2 a b + b2
(a + b) . (a - b) = (a2 - b2)
Arithmetic progression: Arithmetic progression is a sequence of numbers such that the difference of any two successive members of the sequence is a constant.
For example: Suppose a1, a2, a3, a4, ...... , an-1, an are in sequence of arithmetic progression
Then the first term of an arithmetic series is a1 and assume that the common difference of successive members is d, then the nth term of the sequence is:
an = a1 + (n - 1).d
The sum of all the components of an arithmetic series is:
Sn = a1 + a2 + a3 + ....... + an-1 + an
i.e. Sn = (n).(a1 + an)/2
Calculator for solving arithmetic series

Geometric progression: geometric progression OR geometric series is a sequence of numbers such that the quotient of any two successive members of the sequence is a constant. The ratio of two successive number is called common ratio. The constant ratio must not be equal to 0.
Example of geometric series :
ar1, ar2, ar3, . ....... ., arn-1, arn
The nth term of the geometric series can be defined as:
an = a r(n - 1)
r is called common ratio and n must be greater than 0:
Calculator for solving geometric series

Logarithms:
logb 1 = 0
logb b = 1
logb(X . Y) = logbX + logbY
logb(X / Y) = logbX - logbY
logb(Xn) = n . logbX
logmn . lognm = 1

dC = 0
dx

d(Cu) = C du
dx dx

d(u + v) = du + dv
dx dx dx

d(u . v) = u dv + v du
dx dx dx

d ( u ) = v (du/dx) - u (dv/dx)
dx v v2

d ( u n ) = n u n-1   du
dx dx

d ( x n ) = n x n-1  
dx

d ( C u ) = C u ln(C) du
dx dx

d ( e u ) = e u du
dx dx

d( ln(u)) = 1 du
dx u dx

d( sin(u)) = cos(u) du
dx dx

d( cos(u)) = - sin(u) du
dx dx

d( tan(u)) = sec2(u) du
dx dx

d( cosec(u)) = - cosec(u) . cot(u) du
dx dx

d( sec(u)) = sec(u) . tan(u) du
dx dx

d( cot(u)) = - cosec2(u) du
dx dx

d(sin-1u) = 1 du
dx dx

d(cos-1u) = -1 du
dx dx

d(tan-1u) = 1 du
dx 1 + u2 dx

d(cot-1u) = - 1 du
dx 1 + u2 dx

d(sec-1u) = 1 du
dx |u| dx

d(cosec-1u) = -1 du
dx |u| dx